Question

What is a polynomial function in standard form with zeroes 1, 2, –3, and –3?

Answer 1

ou can't have a quadratic function with four zeros.
This will be a quartic function (4th degree polynomial function)

zeros 3, 1, 2, −3 -----> polynomial has roots (x−3), (x−1), (x−2), (x+3)

f(x) = a (x−3) (x−1) (x−2) (x+3)
f(x) = a (x−3)(x+3) * (x−1)(x−2)
f(x) = a (x² − 9) (x² − 3x + 2)
f(x) = a (x⁴ − 3x³ + 2x² − 9x² + 27x − 18)
f(x) = a (x⁴ − 3x³ − 7x² + 27x − 18)

Answer 2

you*

Answer 3

if you're flipping the signs wouldn't it then be (x+3) (x−1) (x−2) (x+3)?

Answer 4

would it?

Answer 5

What have you learned?

Answer 6

Not a whole lot. really confused

Answer 7

Are you homeschooled?

Answer 8

oh, it would be (x+3) (x−1) (x−2) (x+3)

Answer 9

hartnn is good at it

Answer 10

with your comment, even you seem to be good..

Answer 11

pshhhhhhh, www.google.com

Answer 12

works quite well

Answer 13

google doesn't work as well as you think.

Answer 14

http://www.algebra.com/algebra/homework/complex/Complex_Numbers.faq.question.117426.html this is kind of like a mini teacher

Answer 15

not really helping me, sorry

Answer 16

f(x) = (x−3) (x−1) (x−2) (x-3)
now its just algebra...

Answer 17

its too much like geometry. I just don't grasps the concepts very well

Answer 18

still need some help. not askin for and answer just a nudge in the right direction

Answer 19

f(x) = (x−3) (x−1) (x−2) (x-3)
can u foil ?
f(x) = (x^2-6x+9) (x−1) (x−2)

Answer 20

yes I can foil. though should it be x+3 since they're negative to begin with. that be what is confusing me. and not sure how to foil with three numbers

Answer 21

ok,
if a is a zero, then x-a is the factor
if -3 is a zero, then x+3 is the factor

Answer 22

it should be then,
f(x) = (x+3) (x−1) (x−2) (x+3)
f(x) = (x^2+6x+9) (x−1) (x−2)

Answer 23

(x−1) (x−2)= ... ?

Answer 24

x^2 - 3x + 2

Answer 25

right, so u have
f(x) = (x^2+6x+9) (x^2-3x+2)
so u have difficulty foiling this ?

Answer 26

its this step I'm having trouble with. because I ended up with x^4 + 7x^2 + 108

Answer 27

ok, first multiply x^2 (of (x^2+6x+9) ) with (x^2-3x+2)

Answer 28

what u get ?

Answer 29

x^4

Answer 30

just x^4 ?
there will be 3 terms , right ?

Answer 31

x^4 - 3x^3 + 2x^2?

Answer 32

yes, thats correct
now multiply 6x (of (x^2+6x+9) ) with (x^2-3x+2)

Answer 33

6x^3 - 18x^2 + 12x

Answer 34

yes, thats correct
now multiply 9 (of (x^2+6x+9) ) with (x^2-3x+2)

Answer 35

9x^2 - 27x + 18

Answer 36

now add all the 3 results, and that will be your answer.

Answer 37

oh okay. Thank you =^..^=

Answer 38

if u want me to verify, then write what final answer u got...

Answer 39

x^4 + 3x^3 - 7x^2 - 15x + 8

Answer 40

i get 18 in the end

Answer 41

+18, other terms are correct

Answer 42

my bad its a typo. I meant to put 18

Answer 43

then its correct