Question

What? Dont understand... Help anyone
Solve: |5x + 2| + 7 < 19

A. x < 2 and x > -14/5
B. x < 2 and x < -14/5
C. x > 2 and x > 14/5
D. x > 2

Answer 1

|5x + 2| + 7 < 19
|5x + 2| < 19 - 7
|5x + 2| < 12
-12 < 5x + 2 < 12
-12 - 2 < 5x < 12 - 2
-14 < 5x < 10

Divide all sides by 5 to finish

Answer 2

so b)?

Answer 3

first solve the problem assuming that the part in the absolute value brackets is positive. so 5x+2+7<19. to solve for x, subtract 7 and 2 from both sides. so 5x<10. then divide by 5. x<2. then assume that the part in absolute value brackets is negative and solve for x.
-5x-2+7<19.
-5x<14
whenever you divide by a negative, switch the inequality sign so
x>-14/5

Answer 4

Not b bro. Make sure you are paying close attention to the signs. Don't confuse yourself @jackyluvv
@oddfishout, no need to divide by a negative for this one.

Answer 5

why not.... -(5x+2)= -5x-2....right....

Answer 6

Bro |5x + 2| = 5x + 2
Don't use negatives when you don't need to

Answer 7

Dude. We got the same answers, just differently... no biggy. To each his own.

Answer 8

Yeah, but you did yours the hard way. I am not in agreement with your strategy.

Answer 9

so....that is totally okay with me. But it doesn't make me wrong.

Answer 10

All you need to remember is this rule for absolute value:

|x + a| < c means the same as -c < x + a < c