True or false? How do you figure that out? (picture below)
what did you do ?
I haven't done anything, that's the question..
i think you are supposed to replace \(x\) by \(60\) and see if you get the same answer on both sides
lol i meant,,what have you tried in the question! :D
since \(\frac{60}{2}=30\) the left hand side will be \[\tan(30)=\frac{1}{\sqrt 3}\]
oh, @shubhamsrg I haven't tried anything because I didn't know what I was doing :P @satellite73 I'll try that & see what I get. But I didn't know if I'd have to use the equation tan(x/2)=sqrt((1-cosx)/(1+cosx))
that is not the way i read the question is does say \(x=60\) right? also i am confused because the denominator is written as \(\sin^2(x)\sin(x)\) which is usually written as \(\sin^3(x)\) is there a typo there?
Maybe? I just took a screen shot of the question.. but it has said things like that before in other lessons, so they may have meant it that way. & Thanks for helping y'all!
then i would go with what it says.
Okay, thanks so much:)
& I got 4sqrt(3)/3 so I think it's false
i get http://www.wolframalpha.com/input/?i=%281-cos%2860%29%29%2F%28sin^3%2860%29%29 and it is indeed false
That's what I meant :P
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