an isosceles triangular prism has a height of 9 in a base length of 7.2 and a base height of 6 in and base legs of 7 in what does it look like?
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OpenStudy (mathstudent55):
|dw:1355963654269:dw|
OpenStudy (anonymous):
thank you :D
OpenStudy (mathstudent55):
|dw:1355963841226:dw|
OpenStudy (mathstudent55):
wlcm
OpenStudy (anonymous):
and whats the big B ?
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OpenStudy (mathstudent55):
Where's big B?
OpenStudy (anonymous):
the Big b is the area of the base
\[B =bh\]
OpenStudy (mathstudent55):
The area of the base is A = (1/2)bh, where b = base of base triangle called here base length) and h = height of the base.
OpenStudy (anonymous):
im confused (/.\) homework blows
OpenStudy (anonymous):
how do i find the lateral surface area or this figure?
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OpenStudy (mathstudent55):
The lateral surface is the total area of the three vertical sides.
They are all rectangles.
The front one has measures 7.2 in. and 9 in.
The two side ones have the same measures of 7 in. by 9 in.
You need to add the area of three rectangles, but two of them are the same.
Lateral Area = (7.2 in. x 9 in.) + (7 in. x 9 in.) + (7 in. x 9 in.)
Lateral Area = (64.8 + 63 + 63) in.^2 = 190.8 in.^2