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lim x→infinity of [ (sqrt of 4x^6 − x) / (x^3 + 9)]
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\[\lim_{x \rightarrow \infty} \frac{ \sqrt{4x^6-x} }{ x^3+9 }\]
from your eyeballs \[\frac{\sqrt{4x^6}}{x^3}=\frac{2x^3}{x^3}=2\]
Oh so the whole limit is \[\lim_{x \rightarrow \infty} of 2\]
is the answe 2?
yes, the answer is 2
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oh wow I didnt even see that it was equivalent to 2! thanks
yw, i did cheat a bit by ignoring the unimportant terms at the end
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