Question

answers !!!!
qs 6
a) and b) L/(rw+rl)
c and d) go to sandbox, make the circuit, take a f=1/(2*T) and a 5ms trans and measure vmax and vmin

Answer 1

@chaand.i check dis.

Answer 2

thats correct aparna! now can u put a transient anlalysis graph pic here?

Answer 3

ok 1 min

Answer 4

aparna,do 1 thing,attach ur file showing transient analysis and then tell , where is vmax and where is vmin, i mean at what time do you measure them?

Answer 5

this is v min

Answer 6

@jason10 , i am attaching my transiant analysis , kindly now tell me the answer for last two parts from these graphs.

Answer 7

capture 3 n4 r my values n i got it right

Answer 8

@jason10 , i have attached my file , can u tell me the answer for last two parts ????

Answer 9

@chaand.i for vmin u need to place the pointer a the min value i.e at 2ms(ur snap) n for max u need to place it at max peak value

Answer 10

@aparna.b , what is the stop time we need to set ? is that 5ms always ?

Answer 11

I checked two points of tran and my vmin value became bigger than vmax, it's ok?

Answer 12

it ur wish. we can use even 10ms. but time time u choose must be very small n in ms

Answer 13

@aparna.b , my vmin = 42.22m and vmax = 5.925 .. is it ook ?

Answer 14

@fatdrfrog vmin will be smaller than vmax. i think u calculated as V. its not V its mV

Answer 15

@chaand.i i think they r ryt.

Answer 16

but @aparna.b , i am getting confused that how vmin can be 42.22m ?? :/

Answer 17

vmin is the min voltage across resistor. n if u point ur marker at min value u get dat

Answer 18

y is it that sum r getting it ryt n sum r getting it wrong?

Answer 19

i dunno. but wat method i did is right.

Answer 20

@jason10 am I right please check i am left with last check.
i got part c as 4.32
and part d as 0.67
please tell me the answer i got 1st two green ticks, last two left.

Answer 21

V0=5V, T=1ms, Rw=1Ω, Lw=1mH and RL=1Ω.
vmax = ????
vmin = 0.67
4.308 and 4.328 are wrong, and I have only one check

Answer 22

@chaand.i
I have the following values :V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω.. i have a=0.1, b=0.1, c= 7.942. still having problems with d.

Answer 23

for question 6