Mathematics
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OpenStudy (anonymous):
What is the solution of the equation? Helpp!
sqt2x+13 -5=x
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Parth (parthkohli):
\[\sqrt{2x + 13 - 5} = x\]?
Parth (parthkohli):
Or is it\[\sqrt{2x + 13} - 5 = x\]
OpenStudy (anonymous):
The second equation! (:
Parth (parthkohli):
Okay :)
Start with adding \(5\) to both sides.
OpenStudy (anonymous):
can you explain to me what sides?
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Parth (parthkohli):
Add \(5\) to both sides, like this:\[\sqrt{2x +13} - 5 + 5 = x + 5\]
OpenStudy (anonymous):
ok
Parth (parthkohli):
So, what do you have now?
OpenStudy (anonymous):
\[\sqrt{2x+13}=x+5\]
Parth (parthkohli):
now square both sides :-)
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OpenStudy (anonymous):
\[\sqrt{13}=5\]
OpenStudy (hba):
@kudrick16
Lets see this question :)
\[\sqrt{2x+13}=x+5\]
Squaring both sides
OpenStudy (hba):
\[(\sqrt{2x+13})^2=(x+5)^2\]
Hint :
Use (a+b)^2 formula.
OpenStudy (hba):
@kudrick16
Please solve...
OpenStudy (anonymous):
\[\sqrt{169}=25\]
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OpenStudy (anonymous):
25x*
OpenStudy (hba):
@kudrick16
(a+b)^2=a^2+2ab+b^2
(x+5)^2=
\[\sqrt{2x+13}=(2x+13)^{1/2}\]
OpenStudy (hba):
@kudrick16
I think you need to work on your basics first ...
OpenStudy (anonymous):
Now i don't know have a clue what too do from here on out
OpenStudy (anonymous):
well can you explain to me how to do the problem from here?