Write the equation of a line in point slope form that has a slope of -3/4 and passes through the point (4,5)
Use the formula \[y-y_1=m(x-x_1)\] Where, \[m=-3/4,(x_1,y_1)=(4,5)\]
@undeadboss got it dude ?
yeah im trying
so the slope is y? right?
m represents the slope, in this ques m=-3/4
i had a brain fart and now i cant figure it out
whats the equation?
Alternate method, Equation for a line in slope form is given by, y=mx +c where m represents slope and c represents a constant. Let the line y=mx+c pass from given points (4,5) So now we have x=4 and y=5, also m=>slope=-3/4 now put these values in the equation of line as they must satisfy this eqn, from this, you will get the value of C now put the value of c and m in y=mx+c, you will get the required equation.
i mean the end result
try this method, u will get the ans
the former method by hba is derived from this only.
y-b = m(x-a) is this the right equation
this also right, same as one by hba here a,b represent the point passing through the line and m represents the slope so, a=4, b=5 and m=-3/4 Put these value and you will get the desired eqn
got it?
yep thx
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