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Mathematics 19 Online
OpenStudy (anonymous):

a wedding planner must select from 4 possible venues for an actual wedding, and 3 venues for the reception. how many arrangements are possible ?

OpenStudy (anonymous):

12 assuming there has to be a reception, 16 if no reception is an option

OpenStudy (anonymous):

how do you come up with that ?

OpenStudy (anonymous):

i came up with 24

OpenStudy (anonymous):

ok so start by thinking of the possibilities: wedding venue 1 and reception venue 1 wedding venue 1 and reception venue 2 wedding venue 1 and reception venue 3 that's 3 solutions for one given wedding venues and repeat for the other 3 wedding venues that multiplies this result by 4: 3x4 = 12 we have covered all possibilities

OpenStudy (anonymous):

i did it by doing 4!/4-3!

OpenStudy (anonymous):

If there is a rule that justifies what you are doing there then great! but its always good to be able to think it through logically if all else fails!

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