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if tan(A+B) : tan(A-B) = 1 : 2 and Sin 2A + K Sin 2B = 0 , then find the Value of K ?
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@waterineyes @satellite73
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@shubhamsrg @hartnn
sin(a+b) cos(a-b) / sin(a-b) cos(a+b) = 1/2 =>sin(2a) + sin(2b) / sin(2a) - sin(2b) = 1/2 we know, sin2a /sin2b = -k on little observation/substitution , we see we have -k +1 / -k -1 = 1/2 just solve for k
thxxxx
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