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Mathematics 19 Online
OpenStudy (anonymous):

Find the distance between I and J.

OpenStudy (anonymous):

are they vectors?

OpenStudy (anonymous):

I tryed to draw it what I had was a line straight down & then cross it in the middle then theres J(3,2) with a black dot under the 3 & a x to the right of the middle line then on the left under the line this is there /(-5,-4)

OpenStudy (anonymous):

& a black dot above the 5

OpenStudy (anonymous):

I don't know if they are vectors or not

OpenStudy (anonymous):

Need help

OpenStudy (anonymous):

could you upload an image of it or something?

OpenStudy (anonymous):

u have given the cordinates of J cam u give the same for I

OpenStudy (anonymous):

i think ans is 10 units

OpenStudy (anonymous):

ithink the question is to find the distance between I(-5,-4) and J(3,2)

OpenStudy (anonymous):

|dw:1356161987814:dw|

OpenStudy (anonymous):

u can use simply the distance formula to find the distance between (x1,y1)& (x2,y2) which is d= sqrt((x2-x1)^2 +(y2-y1)^2)

OpenStudy (anonymous):

Theres a black dot below the 3 & a black dot above the 5

OpenStudy (anonymous):

if you have the two coordinates, all you have to do is find the difference in both the x-axis and y-axis and then square both numbers, add them together and compute the square root.

OpenStudy (anonymous):

thus reqd distance is sqrt((-5-3)^2 +(-4-2)^2) =sqrt(64+36)=sqrt(100)=10

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