Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

can someone please help me with four Rational Expressions?

OpenStudy (anonymous):

here are the questions

OpenStudy (hba):

\[\frac{ x }{ 3x }+\frac{ 2x-3 }{ 3x }\] Start by taking lcm.

OpenStudy (hba):

@Spartan_Of_Ares Start solving,don't worry i am here with you :)

OpenStudy (anonymous):

whats Icm

OpenStudy (hba):

For example 1/2+1/2 1 + 1 =------- 2 = 2/2 =1

OpenStudy (hba):

@Spartan_Of_Ares Understood ,now take lcm :)

OpenStudy (anonymous):

so then \[x+2x-3/3x\]

OpenStudy (hba):

Yeah and add the things which can be added .

OpenStudy (anonymous):

what can be added?

OpenStudy (hba):

x+2x can be added.

OpenStudy (anonymous):

so i would get 3x or 2x^2

OpenStudy (hba):

You will get 3x so do that and show me what you got.

OpenStudy (anonymous):

so i would get 3x-3/3x?

OpenStudy (anonymous):

and then cancel 3x and 3x?

OpenStudy (hba):

Yeah right for the first comment No lol for the 2nd comment Take common from the upper thing first

OpenStudy (anonymous):

i dont know what you mean

OpenStudy (hba):

\[\frac{ 3x-3 }{ 3 },now \ you \ can \ take \ common \]

OpenStudy (anonymous):

so 3 from the top and three from bottom?

OpenStudy (hba):

But my mistake it was \[3x-3/3x\] and yeah you are right :) So what do you get ?

OpenStudy (anonymous):

3x/x

OpenStudy (hba):

@Spartan_Of_Ares Gone mad ? I told you to take common first. Show me the steps.

OpenStudy (anonymous):

x+2x-3/3x --> 3x-3/3x --> 3?

OpenStudy (hba):

You are correct till 3x-3/3x now you have to take common from the numerator 3(x-1)/3x and then cancel

OpenStudy (anonymous):

so i get x-1/3?

OpenStudy (anonymous):

i mean x-1/x

OpenStudy (hba):

What ?

OpenStudy (hba):

Yeah the second one is right

OpenStudy (hba):

x-1/x is correct Bye :)

OpenStudy (anonymous):

bye and thanks

OpenStudy (hba):

Welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!