can somebody help me?????Solve the system. y = -1/3 x + 2 and x + 3y = 3 (0, 1) (1, 0) (3, 1/3) (3/2, 0) no solution
Substitute equation 1 into equation 2. In other words, replace the y in the second equation with the right side of the first equation. So you have\[x +3(-\frac{ 1 }{ 3 }x +2)=3\]Now solve for x and then substitute the x value back into either equation and solve for y.
You will find that there is no such x value here.
wait so you mixed the equations?
If by mix you mean substitute, then yes.
so substirtute the possible answers for the equations?
he substituted for y and then tried to solve for x. however, there is no answer for x. so there's no solution
Since y is isolated in equation 1, it makes sense to replace the y in equation 2 with whatever y equals in equation 1.
so you changed the equation to y=mx+b and then solved for x?
no. in the first equation, y was already solved for in terms of x. so he substituted that into the second equation
i must sound really stupid but can you like show me the steps that you did that?
I did above. Did you see?
x + 3y = 3 x + 3(-1/3 x + 2) = 3
That's exactly what I did.
once you distribute... x + 3(-1/3 x + 2) = 3 x - x + 6 = 3 6 = 3 which isn't correct...so there's no answer for x
Yes, Very good!
does that make sense, emma?
i think so thanks peoples im havng trouble figuring out who to give the medal too though
doesn't matter to me
x - x + 6 = 3 x - x = 3 - 6 0x = -3 x = -3/0 But a number divided by zero is undefined so there is no solution.
A medal is not what's important. What matters is do you understand what we just taught you?
yes much better now:)
thank you
Great! Then I feel a sense of accomplishment!
:)
Do you need help with anything else?
I guess not. Have a great holiday and stay safe.
oh thanks
Join our real-time social learning platform and learn together with your friends!