Question

Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).

Write the equation of the line parallel to the line 4x + 2y = 5 and passing through the point (-3,5).

Write the equation of the line parallel to the line 4x + y = -1 and passing through the point (5,0).

Write the equation of the line parallel to the line 10x - 5y = 8 and passing through the point (2,4).

Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).


A) y = -5x + 15
B) y = -3x + 14
C) y = -2x - 1
D) y = -4x + 20

Answer 1

oh, these.....um....i can really only tell u how to do it..im not good at these

Answer 2

x-3y = 9
change it into general form format which is y =mx +c, so re-arrange your equation
x-9= 3y..
now divide both sides by 3.

Answer 3

i would really like to help, but these i have no idea how to do :(

Answer 4

y = (x/3) - 3 , now compare it with
y = mx + c
m= gradient.

Answer 5

so what would be the gradient of this line @johana ?

Answer 6

they are matching problems

Answer 7

ya i figured that up but you still have to find the equation of each line of your question.

Answer 8

hmm so?

Answer 9

idk how to do it ??? can u show me step by step

Answer 10

for 1st
x-3y = 9 change it into general form format which is y =mx +c, so re-arrange your equation
x-9= 3y..
now divide both sides by 3.
y = (x/3) - 3 , now compare it with
y = mx + c
m= gradient.
can you tell me by comparing what is m now?

Answer 11

For the last one:
Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).

Perpendicular lines have opposite slopes. Passing through the points (2, 5)

Plug that into Point-Slope form.

y - 5 = 1/5(x - 2)
y - 5 = 1/5x - 1
y = 1/5x + 4 <-- Equation.

Answer 12

oh ok i got it how to do it thank you so much :))

Answer 13

Thanks, nubeer, for helping her, too.

Answer 14

:))