Question

2. Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?

A. 4
B. 8
C. 12
D. 13
E. 16

Answer 1

remember worst case usually wins... what if she draws all of the red ones first.... and then draws all the same(other than red) color next...either all blue or all green... there is 4 of each of then colors....

Answer 2

8+4 = 12.... thats the worst case.... she could pick 8 red ones first... and 4 of a different but same color next.... so on the very next pick should would "defiantly" have picked one of each

Answer 3

remember multiple choice questions we can do away with the wrong ones to help find the right ones easier... we know it isn't 4, 8, or 12, so we can do away with those

Answer 4

on these types of questions it may help to take out some pennies nickles dimes etc, to help you figure out your answer... let one be one color, and another be another color... start with the highest value given, in this case, 8 red ones, were use pennies for those, and 4 nickles, and 4 dimes for the green and blue ones.... ok, worst case... pick out all the highest or most ones of the same... (the red ones, pennies) we took away 8 from our stack of 16 coins.... now take away all of the same of the next highest ones/colors... in this case since there both 4, it wont matter rather you take away the nickles or dimes/green or blue ones.... we now took away 12 coins from our stack of 16.... were left with just one color/one type of coin.... if we draw one more from the remaining stack we would have drawn one type/color from each stack.... 12+1 is our answer so 13