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Mathematics
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A group contains fi ve men and fi ve women. How many ways are there to arrange these people in a circular table with ten seats if men and women alternate, and the seatings are considered the same if each person has the same right neighbor and left neighbor?
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I would think of it as a line of people, rather than a circle. m1, f1, m2, f2, ... m5, f5 This is the same as: f5, m1, f1, m2, f2, ... m5 So basically, for every assignment, there are 10 redundant versions of it.
Now, to find the assignments, you'd have: 5m, 5f, 4m, 4f, ... 1m, 1f. In other words, you'd have: 5! * 5! main assignments.
So I'm getting: 5! * 5! / 10
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