The answer is no solution right? Solve the system, using substitution. Write the solution as an ordered pair (m, n). 2m - 3n = 6 and m = 3 - 2n (6, 2) (3, 0) (-3, -4) (0, 2) no solution
I would turn them into lines:\[ 2m - 3n = 6 \implies 2m = 6 + 3n \implies m = 3+1.5n \\ m = 3 - 2n \]These lines do not have the same slope (one is -2, the other is +1.5), so they aren't parallel. So they should eventually hit for some value of \(n\).
\[ 3-2n = m = 3+1.5n \implies 3-2n = 3+1.5n \]Solving for \(n\) here should tell you the solution, I believe.
look i did the work i changed m=y and n=x ok 2x-3y=6 and x=3-2y 2(3-2y)-3y=6 6-4y-3y=6 6-1y=6-6 -1y/-1=0/-1 so tha would make it no solution bcs its not possible to get x after that
Though the substitution method they mentioned would mean doing this: \[ 2m - 3n = 6 \wedge m = 3 - 2n \implies 2(3-2n) - 3n = 6\\ 2(3-2n) - 3n = 6 \]
so would i get -1/0?
Okay so -1y/-1=0/-1 means y = 0
Then plug that into another equation: x=3-2y x=3-2(0) x=3-0 x=3
ok ok so that means the answer is 3,0 ?
x = 3, y = 0 (3, 0)
thank you for your help:)
No, because you switched m and n
(m, n), means m is x and n is y.
i wrpte 3,0 up there didnt you see?
Oh, ok
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