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Mathematics 14 Online
OpenStudy (anonymous):

Factor: 6x^3y-18x^2 y^2+12xy^3

OpenStudy (inkyvoyd):

factor out the constant to make it easier 6(x^3y-3x^2y^2+2xy^3) tell me if you need more help.

OpenStudy (anonymous):

not sure what to do next

OpenStudy (inkyvoyd):

Try factoring by grouping.

OpenStudy (anonymous):

Alright. After, you need to factor out xy. Then 6xy(x^2-3xy+2y^2) From here you need to do this: (x+ )(x+ )

OpenStudy (anonymous):

now with the 2y^2 you need to break that down into 2y*y. Except since the middle term in negative, it would be -2y and -y.

OpenStudy (anonymous):

So your final factorization would be (x-2y)(x-y)

OpenStudy (anonymous):

wait 6xy(x-2y)(x-y)

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