Question

In acceleration vs time grapg of a Particle covering a distance of 40m from t=2 till t=4s The magnitude of Velocity at t= 10s

Answer 1

I am nt sure if this is right.
Using s=ut+1/2at^2
40=2u+1/2*5*4
40=2u+10
2u=40-10
2u=30
u=30/2
u=15
using v=u+at
v=15+5*2
v=15+10
v=25
The area

Answer 2

25 + 15 = 40

Answer 3

right ?

Answer 4

1/2 * 5 * 6 = 15

Answer 5

yup:)

Answer 6

but @ajprincess i want to know why Area under this Graph results in 30 m/s

Answer 7

It is not given that the particle starts from rest. so it might have had an initial velocity. From the graph acc is only zero at first nt the velocity.

Answer 8

does that make sense @yahoo?

Answer 9

What exactly are you supposed to find ?

Answer 10

The magnitude of Velocity at t= 10s

Answer 11

thxxx

Answer 12

welcome:)