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OpenStudy (ajprincess):
\((a-b)(a+b)=a^2-b^2\)
Plug in \(x^5\) in place of a and \(y^2\) in place of b. Can u do @cdelomas?
OpenStudy (anonymous):
can you help me
OpenStudy (anonymous):
would it be 3
OpenStudy (ajprincess):
no
In \(a^2-b^2\) plug in \(x^5\) for a and \(y^2\) for b. nw can u do.
OpenStudy (anonymous):
is it 5*2
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OpenStudy (anonymous):
are you still there
OpenStudy (ajprincess):
Nope.
\((x^5+y^2)(x^5-y^2)=(x^5)^2-(y^2)^2\)
using \(\large(c^d)^e=c^{d*e}\)
\((x^5)^2-(y^2)^2=(x^{5*2})-(y^{2*2})\)
=\(x^{10}-y^4\)
getting this? If u dnt get any of this plz ask:)
OpenStudy (anonymous):
where did c,d,e comefr om
OpenStudy (ajprincess):
They are jst part of general formula>
OpenStudy (anonymous):
iGOTEVe ry thing else
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
So what would beth e product
OpenStudy (anonymous):
hello
OpenStudy (ajprincess):
That's what I gave u. Guess u still didnt get me. so please if u dnt understand anythng ask me. I will try my best to explain u.:)
OpenStudy (anonymous):
no I got it just did not k now if that w as the product.
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