Question

x^2-8x+7 factor the trinomial

Answer 1

(x-7)(x-1)
-7*-1 = 7
-7+(-1) = -8

Answer 2

so is that it -8

Answer 3

so jenychan is it -8

Answer 4

no. it's (x-7)(x-1)
you're looking for two numbers that add up to -8 but multiply to 7
(if you want you can set up xn = 7 and x+n = -8)
WORK:
x*x = x^2
-7*-1 = 7
-7+(-1) = -8

Answer 5

4 and 2

Answer 6

.....
no. 4 and 2 don't add up to 8 nor do they multiply to 7
(7 is a prime number)

Answer 7

maybe it cannot be factored

Answer 8

i do not get it

Answer 9

so you have x^2-8x+7 right?
the middle term (-8x) means that you're looking for two numbers that'll add up to -8. There are many possibilities. Don't look at this term first.
Let's look at +7. What times what gives you 7? Well, we know that since 7 is a prime number, you can only have 7*1 or -7*-1 right? But 7+1 = +8, not -8, so our only choice is -7 and -1 so it'd be (x-7)(x-1)

Answer 10

thanks