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use the square root property to solve the equation (5x+5)(exp. 2)=100
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square root both sides then solve for x |dw:1356910197873:dw|
x=1?
Yes :)
Hold on!
k
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\[(5x+5)^2=100\]\[5x+5=\pm10\]
OOh crap forgot about that! Whenever you square root don't forget to put plus or minus!
my answers are 0,1? 1,4? 14 -14? 1, -4?
5x + 5 = ±10 5x = -5 ± 10 x = -1 ± 2 x = 1 or x = -3 Not sure why it's not in your answers
when 5x+5=+10, then x=1 when 5x+5=-10, then x=-3
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you guys are right... im soo sorry, i was looking at another problem.... thank u.. my bad.
can you help me with, (2x+3) (exp 2) =25
Same process, square root both sides first!
5?
You get 2x+3 = ±5
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ok yeah
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