Question

integrate sin^2n dx from 0 to pi

Answer 1

is it sin^2x ?

Answer 2

Do you mean:
\[\int\limits_{0}^{2 \pi }\sin^2(x)dx\]

Answer 3

sorry, i mean 0<x< pi

Answer 4

i mean sin ^2n theta dtheta using cauch integral

Answer 5

Using cauchy integral?! Really?!

Answer 6

\[\int\limits_{0}^{\pi}\sin ^{2}ntheta \]

Answer 7

yesss.. using cauchy integral. sin ^(2n)

Answer 8

There's a formula for sin which You can use, I can't remember it at the top of my head, but it's something like:
\[\frac{ e^x+e^{-ix} }{ 2 }\]
I think? Does that look familiar to yopu?!

Answer 9

For continuous functions, you use u(t) +iv(t) on a<theta<b?