Question

find the zeros and multiplicity of y = (x-5)(x+2)^2

Answer 1

You have to solve\[(x-5)(x+2)(x+2)=0\]Ask yourself: when is a product 0? The answer is of course if one of the factors is 0.
Factors here are: x-5, x+2 and x+2 (again, hint!)
I think you can see what x can be now...

Answer 2

oh okay thank you, so the zeroes are 5,-2,-2 right?, but how do I find the multiplicity

Answer 3

@ZeHanz

Answer 4

The multiplicity stares you in the face ;)
5: I see only one >> multiplicity 1
-2: I see two of them >> multiplicity 2

Answer 5

ohhhh, hahahahah, got it thank you

Answer 6

yw!