Question

find area under curve

Answer 1

y^2-4x=4 and 4x-y=16

Answer 2

i found intercept point -1 and -4 ?

Answer 3

x=-1 and x=-4 wow is it true all user !!!!

Answer 4

no...

Answer 5

im solving patience

Answer 6

and do it about the y axis

Answer 7

i got 109+25/2

Answer 8

\[\int\limits_{-4}^{-1}\frac{ -4+y^2 }{ 4 }-\frac{ 16+y }{ 4 }\]

Answer 9

this is how i got my answer

Answer 10

nvm 243/8 and its about y
so use 5, -4 as the limits

Answer 11

how did u get thoe -4 and -5

Answer 12

\[0=4+4x\]

Answer 13

\[0=-16-4x\]

Answer 14

right
what u need to do is set the equations equal to each other. You do this by putting them both in terms of y.
so x=\[\frac{ 16+y }{ 4}\]
and x=\[\frac{ y^2-4 }{ 4 }\]
so solve and get y=5,-4

Answer 15

does this make sense? if u graph it...you would integrate about the y...

Answer 16

did u set them =0

Answer 17

no...

Answer 18

you set them equal to each other...and when you move the equations to one side. you have a zero on the othe rside

Answer 19

never mind got it

Answer 20

kk am i best responder

Answer 21

it would really help to give me a medal :D

Answer 22

for all my hard work

Answer 23

lol

Answer 24

lol im a noob only lvl 52

Answer 25

yusss beat you all to it :p

Answer 26

Take a look:

Integrate 2sqrt(4 + 4x) from x = -1 to 3

and then integrate sqrt(4 + 4x) - (4x - 16) from x = 3 to 5.25

add them

Answer 27

cold mold on a sssssl8 pl8

Answer 28

any of yall in calc BC

Answer 29

Looks like: