Question

A rectangular garden has a perimeter of 92 feet. If the length of the garden is 1 foot greater than twice its width, what is the length of the garden in feet?

Answer 1

Step 1)

Make two equations.

2l + 2w = 92

l = 1 + 2w

Answer 2

The perimeter of a rectangular garden is 326 feet. If the length of the garden is 95 feet, what is its width?

Answer 3

Now use substitution.

Substitute the value of l into the first equation. Solve for w.
2l + 2w = 92
l = 1 + 2w
__
2(1 + 2w) = 92
Distribute the 2.
2 + 4w = 92
Subtract 2.
4w = 90
Divide by 4.
w = 22.5

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Substitute the value of the width (w = 22.5) into any equation. Solve for l(length).
2l + 2w = 92
2l + 2(22.5) = 92
2l + 45 = 92
Subtract 45.
2l = 47
Divide by 2.
l = 23.5

Length is 23.5

Answer 4

@leebulls

Answer 5

The perimeter of a rectangular garden is 326 feet. If the length of the garden is 95 feet, what is its width?

P = 2l + 2w

326 = 2(95) + 2w

326 = 190 + 2w

Subtract 190.

136 = 2w

Divide by 2.

68 = w

Width is 68.