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if you subtract 13 times a number from its square, the result is -36 translate into an equation and find the factors
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13 times a number=13x its square=x^2 so, x^2-13x=-36 do you know how to solve it from here?
no
Move the -36 over so the equation is equal to 0... x^2-13x+36=0 you've never done factoring?
k but from there
all i know is 9 and 4 but is one negtive positive???
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theyre both negative because -9-4=13 and -9*-4=36
typo i meant -13
k ty for your help
So you got (x-9)(x-4) as your factors right?
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