the length of a rectangle is 6 more than the width, the area of a rectangle is 16m^2 find the length and width

Question

anonymous · Answer

Let $x$ be the width and $y$ be the length.
What sort of equations do they tell us?

anonymous · Answer

"the length of a rectangle is 6 more than the width"

How to we write this in terms of $x$ and $y$?

anonymous · Answer

"the area of a rectangle is 16m^2 "

and how do we write this in algebra?

anonymous · Answer

@ricque Got an idea?

anonymous · Answer

whats that

anonymous · Answer

Here's a hint:

"the length of a rectangle is 6 more than the width"
becomes 
"y is 6 more than x"
since we said "Let x be the width and y be the length."

Can you

anonymous · Answer

Can you make it into a full on math equation?

anonymous · Answer

no

anonymous · Answer

1) Let x be the width and y be the length.  (our choice)

2) "the length of a rectangle is 6 more than the width"
"y is 6 more than x"
"y = 6 more than x"
y = 6 + x

3) "the area of a rectangle is 16m^2 "
"xy is 16m^2"
xy = 16m^2

So we have two equations:

y = 6 + x
xy = 16

Can you solve it?