Question

use the quadratic formula to find the zeros y=2x^2+8x+1

Answer 1

Quadratic formula to be used is:
\( x=\frac{-b\pm\sqrt{n^2-4ac} }{2a} \)
where a,b,c refer to an equation
\( ax^2+bx+c=0 \)
Here a=2,b=8,c=1.
Can you find x?

Answer 2

can you help more

Answer 3

Substitute a=2, b=8, c=1 into the quadratic formula to get:
\( x=\frac{-8\pm \sqrt{8^2-4(2)(1)}}{2(2)} \)
Can you then evaluate that with a calculator or by hand?

Answer 4

is there more to this problem, not getting an answer that i have to choose from

Answer 5

What did you come up with, and what are the choices?