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Write an equation of the line that passes through the point (3,0) and has the slope, m = -2. PLEASE HELP!!!
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HELP!!!
Use point slope formula: \[y-y _{1}=m(x-x _{1})\]
so would the answer be y=-2x-3?
Almost, you need to distrubute the -2 to the -3. \[y-0=-2(x-3)\] \[y=-2x-(-2)3\]
ooh thanks almost forgot ^.^ thanks
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so its y=-2x+6?
or is it a -6 instead?
A negative times a negative will give you a positive. So the positive is correct.
thanks bunches
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