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\[2\sqrt{7x }+ \sqrt{7x}-3\sqrt{7x} ^{-7}\]
just combine the like terms for the first two, I forget how to do the rest.
\[that would be 3\sqrt{7x}\]
Yes.
then what i subtract the 2 and -3
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I forget how to do the rest, I'm an eighth grader taking 10th grade math..lol
Actually, you can't because \( \sqrt{7} \neq \sqrt{7}^{-7} \)
im in 9th doing algebra 2 but i never took alg 1
so the answer is just like -7
\( 3\sqrt7 - 3\sqrt7^{-7} \) is in the simplest form, if this is what you want.
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O yes
thanks you guys and girls
Glad we helped.
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