Question

Plz give me a tutrial on perfect square method for quadratic equation :)

Answer 1

Lets take an example :
x^2 + 6x+8 =0

Answer 2

Step 1 : what is the co-efficient of 'x' ?

Answer 3

6

Answer 4

step 1 : Divide it by 2.

Answer 5

step 2 *

Answer 6

3x

Answer 7

step 3 :Square it.

Answer 8

not 3x, just 3

Answer 9

9x

Answer 10

where are 'x's coming from ???

Answer 11

the co-efficient of 'x' is just 6

Answer 12

ok sorry

Answer 13

it's just 9

Answer 14

step 4 : Add and subtract 9 .

Answer 15

To whom i add & subtract 9

Answer 16

I mean which number

Answer 17

\(x^2+6x+9 -9+8=0 \\ x^2+6x+9=9-8\)
get this....

Answer 18

yup

Answer 19

now lefty is a perfect square.

Answer 20

mean left side equation

Answer 21

lol, yes!

Answer 22

Ok! thanx i gt it :)

Answer 23

want to solve for general quadratic ?
\(ax^2+bx+c=0\)

Answer 24

no it's example is given my book

Answer 25

in*

Answer 26

okk...

Answer 27

Another example :
\[x^2 + 4x+5 =0 \]\[\rightarrow (x^2 + 4x+2)+3 =0 \]\[\rightarrow (x +2)^2+3 =0 \]

Answer 28

you mean (x+2)^2+1 ??

Answer 29

ah yes, how did you mess that up.

Answer 30

\[{\color{red}{**}}\]\[x^2+4x+5=0\]\[→(x^2+4x+4)+1=0\]\[→(x+2)^2+1=0\]