Question

is this the correct answer?

Answer 1

Um,What ?

Answer 2

is it b? :)

Answer 3

Yeah right :)

Answer 4

great thanks! :)

Answer 5

You have to use,

\[\sin \theta =P/H\]

\[\sin 30^0=P/2\sqrt{3}\]

\[P=\sin30^0*2 \sqrt{3}\]

\[P=\frac{ 1 }{ 2 } \times 2\sqrt{3}\]

\[P=\sqrt{3}\]

Answer 6

No. The sides of a 30-60-90 triangle are of proportions 1:sqrt3:2. If we apply that proportion to the given triangle, the sides are sqrt3, 3, 2sqrt3.

Answer 7

That is the same as (1:sqrt3:2)*sqrt3