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A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?
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use the kinematic equation for position, x=x(0)+v(0)t+1/2at^2 count the starting point as zero to make it easier, there is no initial velocity, so just pug in 9 seconds into the equation and everything except acceleration cancels so: x=1/2at^2, the gravity of the moon is 1/6 the gravity of earth btw
Why is there no initial velocity ?
because it is being dropped, that implies that it starts from rest
wtf is the damm answer
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