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How do I find the vertex for the quadratic function y=-2(x+3)^2-4 so I can find the other x and why values?
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This is vertex form : y = a( x-h) ^2 +k Where (h,k) is the vertex
Any ideas on what the vertex for yours is?
(3.4) ?
No, not exactly. if it was a(x-h)^2 +k, and you have a +3 for the h value.. thats a double negative.. get it?
But if k is -4 is it (3,-4) ?
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Yes, the -4 is right, but the 3 also needs to be negative because it's x- -3 --> x+3
Oh I see so (-3, -4)
Yep, thats right
Ohk, Thank you!
No problem
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