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Mathematics 7 Online
OpenStudy (anonymous):

How do I find the vertex for the quadratic function y=-2(x+3)^2-4 so I can find the other x and why values?

OpenStudy (anonymous):

This is vertex form : y = a( x-h) ^2 +k Where (h,k) is the vertex

OpenStudy (anonymous):

Any ideas on what the vertex for yours is?

OpenStudy (anonymous):

(3.4) ?

OpenStudy (anonymous):

No, not exactly. if it was a(x-h)^2 +k, and you have a +3 for the h value.. thats a double negative.. get it?

OpenStudy (anonymous):

But if k is -4 is it (3,-4) ?

OpenStudy (anonymous):

Yes, the -4 is right, but the 3 also needs to be negative because it's x- -3 --> x+3

OpenStudy (anonymous):

Oh I see so (-3, -4)

OpenStudy (anonymous):

Yep, thats right

OpenStudy (anonymous):

Ohk, Thank you!

OpenStudy (anonymous):

No problem

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