Find the lowest common denominator for the set of fractions: 6/a^2-7a+6 and 3/a^2-36

Question

anonymous · Answer

do ju mean for both fractions 1 lcd or an lcd for each fraction?

anonymous · Answer

i need the LCD for the 2 fractions

anonymous · Answer

i have a feeling its (a+6)(a-6)(a-1)  but im not completely sure... do ju have answer choices?

anonymous · Answer

i have a fill in box and its _ _ _ 6 _ _ _ _ _ _ _ _ + _ _

anonymous · Answer

@blondie16  is correct... 
if you factor the denominators of each fraction, you'll see why it has to be (a+6)(a-6)(a-1)

anonymous · Answer

woohoo! lol thank ju @dpaInc for making sure

anonymous · Answer

yw... :)

anonymous · Answer

what about 7/x^2+4x+4 and 5/4-x^2

anonymous · Answer

ju still have to factor out the bottom so it would be (x+2)^2(x-2)

anonymous · Answer

i have one more mind helping?

anonymous · Answer

sure

anonymous · Answer

x/x^2-5x+4 and x+1/x^2-16

anonymous · Answer

(x-1)(x+4)(x-4)

anonymous · Answer

thank you so much i may be coming back to you for help in just a minute :) i have another assignment but i think  i got it now

anonymous · Answer

lol alright i think i deserve a medal though xD

anonymous · Answer

im new to this how do i give you a medal

anonymous · Answer

like that LOL

anonymous · Answer

got it i think haha