Question

3/u+2 = 1/u - 2

Answer 1

\[{3 \over u+2} = {1 \over u - 2}\]Is this the question?

Answer 2

yes

Answer 3

1) cross multiply first

Answer 4

2) distribute the constant to each term

Answer 5

3) solve for u using basic algebraic techniques

Answer 6

yes except they are equal not over eachother

Answer 7

Cross multiplying really looks like this\[{3 \over u+2}\times (u+2)(u-2) = {1 \over u - 2}\times (u+2)(u-2)\]Then the appropriate terms cancel

Answer 8

Good job!!

Answer 9

But in your work make sure you only show a division by 2 not 2u.