Question

If I am doing synthetic division on (x^3-14x+8)/(x-2) would my answer be 1x-18+(80/x+4)?

Answer 1

can't be because if you divide a polynomial of degree 3 by a polynomial of degree one you get a polynomial of degree 2

Answer 2

if you want me to make a guess, i would say you might have forgotten to keep the place of the missing \(x^2\) term

Answer 3

Okay, I shall re-try this

Answer 4

the coefficients you list should be
1 0 -14 8
2


etc

Answer 5

where did the 0 come from?

Answer 6

@DanielAcedo your original polynomial is missing the x^2 term. That means the x^2 coefficient is 0 (since 0x^2 = 0 and adding 0 makes no difference).