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MIT 6.00 Intro Computer Science (OCW) 8 Online
OpenStudy (anonymous):

For the bisection search, epsilon governs the divisions. On the video, John Guttag says that 12345 / epsilon^2(0.0001) is about 26.897. I get a totally different number. What am I not getting here?

OpenStudy (anonymous):

Either your epsilon is different or your syntax is wrong. I suspect that your denominator format is incorrect.

OpenStudy (anonymous):

Guttag is talking about the worst case for the bisection search which is log2(N). I was initially confused too, because he doesn't restate the log2(N) when talking about 12345/epsilon^2. N = 12345/epsilon^2 log2(123450000) = 26.897

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