Question

How would i factor f(x)=x^3-3x^2-16x-12 given that f=6 f(6)=0 ?

Answer 1

\[f(6)=x ^{3}-3x ^{2}-16x-12\]

Answer 2

Because f(6)=0, you know that 6 is a solution of the function. THerefore, you get (x-6)(something)=x^3-3x^2-16x-12=0

Answer 3

YOu can then divide the big polynomial by (x-6) and then solve for the rest of the solutions

Answer 4

Wouldn't I divide x^3-3x^2-16x-12=0 by (x-6) ?

Answer 5

that's what I meant by "the big polynomial"

Answer 6

Oh, ok. Thank you!

Answer 7

Do I use synthetic division or the regular division?

Answer 8

doesn't matter. Whichever is easier

Answer 9

Ok, Thanks

Answer 10

Regular

Answer 11

they both do the same thing