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Rewrite with only sin x and cos x. cos 3x
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\[\cos(3x) = \cos(1.5x + 1.5x)\]Use\[\cos(a + b) = \cos(a)\cos(b) - \sin(a)\sin(b)\]
2 sin2x cos x - 2 sin x cos x be my answer
but that has sin2x in it ??
Rather, use \(\cos(2x) = \cos^2 (x) - \sin^2(x)\)
Here, \(x = 1.5x\).
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-sin3x + 2 sin x cos x
Hmm! I think that doesn't work.
cos x - 4 cos x sin2x
\[\cos(x + 2x) = \cos(x)\cos(2x) - \sin(x)\sin(2x)\]So you can use the formulas for \(\sin(2x)\) and \(\cos(2x)\)
-sin2x + 2 sin x cos x
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is my answer
But that has \(2x\) in it
These are my choices, one of them has to fit cos x - 4 cos x sin2x -sin3x + 2 sin x cos x -sin2x + 2 sin x cos x 2 sin2x cos x - 2 sin x cos x
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