Question

2y/xy^2-3x/(x^2y^2) how do you find the difference in these ?

Answer 1

You can't subtract the two fractions until all denominators are equal

Answer 2

right

Answer 3

We can get them equal to the LCD, which in this case is x^2y^2

The second denominator is equal to the LCD, so we don't have to worry about that

Answer 4

the first denominator is xy^2

we want it to get to x^2y^2, so we need to multiply xy^2 by x

Answer 5

okay

Answer 6

we must do the same to both top and bottom of the first fraction to go from

2y/xy^2

to

2xy/x^2y^2

Answer 7

which means

2y/xy^2-3x/(x^2y^2)

is the same as

2xy/(x^2y^2)-3x/(x^2y^2)

now you can subtract the fractions

Answer 8

okay thanks

Answer 9

np