Question

The cubed root of 8x3y6z4 (the 3, 6, and 4 are powers)

Answer 1

the cubed root of 8 is 2
the cubed root of \(x^3\) is \(x\)
the cubed root of \(y^6\) is \(y^2\)

Answer 2

it is supposed to be the cubed root of all of it together it's one problem

Answer 3

the only one that stays inside the radical a \(y\) reason as follows :
3 goes in to 4 one time with a remainder of 1,
one \(y\) comes out, one \(y\) stays in

Answer 4

yes i know

Answer 5

\[\sqrt[2]{ab}=\sqrt[3]{a}\sqrt[3]{b}\] so you can take it apart

Answer 6

no that is wrong final answer should be
\[2xy^2z\sqrt[3]{z}\]