how do you explain to solve a2 + 12ab + 27b2

Question

whpalmer4 · Answer

$$a^2+12ab+27b^2$$
(It really isn't difficult to use the equation entry form, and it makes the problems much clearer for those trying to help you!)

I assume you are trying to factor this expression.

To factor, notice that the final term has a coefficient of 27, which can be created by 3*9, and the middle term a coefficient of 12, which can be created by 3+9.  If our equation can be written as 
$$x^2+(n+m)xy+(n*m)y^2$$ then the factoring is
$$x^2+(n+m)xy+(n*m)y^2 = (x+n)(x+m)$$

We're in luck!  We can write our equation as

$$a^2+12ab+27b^2 = (a+3b)(a+9b)$$

Set (a+3b)=0 or (a+9b)=0 to find the solutions.