Question

Use the Quadratic Formula to solve the equation.

–x2 – x – 5 = 0

Answer 1

@Hero

Answer 2

-x^2*

Answer 3

\[–x^2 – x – 5 = 0\]

1st I would factor out -1:
\[-(x^2 + x + 5) = 0\]

Then divide both sides by -1
\[x^2 + x + 5 = 0\]

Now I would use quadratic formula:

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

a = 1, b = 1, c = 5

Answer 4

Oh, thank you very much :)

Answer 5

Well, actually, hang on

Answer 6

When in doubt, compute the discriminant to see if this is even has any real solution

Answer 7

b^2 - 4ac = (1)^2 - 4(1)(5) = 1 - 20 = -19
No real solution

Answer 8

Thats what i got also, i wanted to make sure i was doing it right. :)