Can anyone figure out what x and y are in this problem using th method: Elimination.? 7x - 3y = 20 5x + 3y = 16 Thanks.(:
is this algebra 1??
Yeah
by sum : 7x - 3y = 20 5x + 3y = 16 -------------- 12x+0=36 x=36/12=3
I know you subtract and end up with 12x = 36 or am I wrong?
ok well, um thats it @baziham lol :)
and by equation 1: 7x - 3y = 20 7(3) - 3y=20 21 - 20 = 3y 1= 3y y= 1/3
Whats x then?
or is there no x? :o
x=3 i write it at the end of first post ok?
I know you subtract and end up with 12x = 36 or am I wrong? almost. you add. you can do it like baz showed,(which is how I would do it) or like this, all on one line 7x +5x - 3y +3y = 20+16 simplify and you get 12x=36 and x= 36/12 or 3
now use x=3 in either equation and solve for y
Oh, I gotcha. And I ment to say add. Lol.
and the reason we add is because we noticed that -3y + 3y is zero, making the y's disappear.
Oh! Thankyou! You all are such a big help.! I was so confused.
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