Question

Okay, Comparing the Square.

Answer 1

\[y=x^{2}-6x+13\]

Answer 2

Do you mean completing the square? Try watching this video and see if it makes sense after: https://www.khanacademy.org/math/algebra/quadratics/completing_the_square/v/ex2-completing-the-square

Answer 3

lol yeah. Sorry, autocorrect

Answer 4

half of 6 is 3 so start \(y=(x-3)^3+k\)
you have a choice of ways to find \(k\)
a) you can replace (x\) by \(3\) in the original equation to see what you get
or
b) you can note that \(3^2=9\) but since you already have 13 you only need \(13-9=4\) so you get
\[y=(x-3)^2+4\]