Question

At the beginning of an experiment there were 120 grams of a radon, after 42 minutes there were only 96 grams of radon remaining. What is the growth/decay rate of radon?

Answer 1

\[\frac{96}{120}=e^{-k\times 42}\] solve for \(k\)

Answer 2

@satellite73 not sure how to

Answer 3

\[.8=e^{-42k}\]
\[\ln(.8)=-42k\]
\[k=\frac{\ln(.8)}{-42}\]

Answer 4

@satellite73 so is -42 the final answer? or ln(.8)/-42

Answer 5

the second one