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OpenStudy (hba):
Is it,
\[\huge\ (x-2)(x+2)=5^1\]
OpenStudy (hba):
@ma12209 ?
OpenStudy (anonymous):
x^2+2x-2x-4=5^1
x^2-4=5
x^2=5+4
x^2=9
x=3
i think hehe
OpenStudy (hba):
@miszery
Giving direct answers is not allowed on OS.
Please let the asker participate.
If you are still not sure please check the CoC-
http://openstudy.com/code-of-conduct
OpenStudy (anonymous):
thanks :) everyone
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OpenStudy (hba):
@miszery Is that understood ?
OpenStudy (hba):
@skullpatrol Not you dude :P
OpenStudy (hba):
@ma12209
You should check this
\[\sqrt{9}=\pm3\]
OpenStudy (anonymous):
sorry I don't understand I didn;t know the answer I was trying to figure it out
OpenStudy (hba):
@miszery I hope you don't do the same think the next time.
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OpenStudy (anonymous):
sorry you guys for the problem i caused.....thanks for your help though ...i think its better if i just dont ask
OpenStudy (hba):
@ma12209
Well the point is that you should participate in the solution :)
Nothing else.
OpenStudy (skullpatrol):
"Ask" but don't demand the answer...
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
ok sorry and thanks
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OpenStudy (hba):
Welcome :)
OpenStudy (skullpatrol):
Remember to try and get involved in the solution process.
OpenStudy (jiteshmeghwal9):
(x-2)(x+2)=5^1
Use the identity
\((a+b)(a-b)=a^2-b^2\)
x^2-4=5
x^2=5+4=9
take square root both sides
\(\sqrt{x^2}=\sqrt{9}\)