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t^2+6t-7=(t+7)(t-1) Can you simplify?
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@boompolis You should start working on it and i will help you where you go wrong.
t^2 + 6t / t-1 - 7 / t-1 t^2 + 6t - 7 / t-1 factoring t^2 + 6t - 7 = (t+7)(t-1) ... now simplify
\(\large{t^2+6t-7=(t+7)(t-1)}\) \(\large{\implies t^2+6t-7=t^2-t+7t-7}\) \(\large{\implies t^2+6t-7=t^2+6t-7}\) Therefore it is true means right :)\[\Huge{\color{red}{\checkmark}}\]
so which one is the simplified answer
@TheViper
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\[\Huge{\color{red}{t^2+6t-7}}\]
thanx
ur welcome :)
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